-3(2n)^2=-6n^2

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Solution for -3(2n)^2=-6n^2 equation: 



-3(2n)^2=-6n^2

We move all terms to the left:

-3(2n)^2-(-6n^2)=0

We add all the numbers together, and all the variables

-32n^2-(-6n^2)=0

We get rid of parentheses

-32n^2+6n^2=0

We add all the numbers together, and all the variables

-26n^2=0

a = -26; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-26)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{-52}=0$

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